3(3x+12)-10=2(x+4)+39

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Solution for 3(3x+12)-10=2(x+4)+39 equation: 



3(3x+12)-10=2(x+4)+39

We move all terms to the left:

3(3x+12)-10-(2(x+4)+39)=0

We multiply parentheses

9x-(2(x+4)+39)+36-10=0



We calculate terms in parentheses: -(2(x+4)+39), so:

2(x+4)+39

We multiply parentheses

2x+8+39

We add all the numbers together, and all the variables

2x+47

Back to the equation:

-(2x+47)



We add all the numbers together, and all the variables

9x-(2x+47)+26=0

We get rid of parentheses

9x-2x-47+26=0

We add all the numbers together, and all the variables

7x-21=0

We move all terms containing x to the left, all other terms to the right

7x=21

x=21/7

x=3

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