2(y+1)-3(y-2)=5(y-1)+1

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Solution for 2(y+1)-3(y-2)=5(y-1)+1 equation: 



2(y+1)-3(y-2)=5(y-1)+1

We move all terms to the left:

2(y+1)-3(y-2)-(5(y-1)+1)=0

We multiply parentheses

2y-3y-(5(y-1)+1)+2+6=0



We calculate terms in parentheses: -(5(y-1)+1), so:

5(y-1)+1

We multiply parentheses

5y-5+1

We add all the numbers together, and all the variables

5y-4

Back to the equation:

-(5y-4)



We add all the numbers together, and all the variables

-1y-(5y-4)+8=0

We get rid of parentheses

-1y-5y+4+8=0

We add all the numbers together, and all the variables

-6y+12=0

We move all terms containing y to the left, all other terms to the right

-6y=-12

y=-12/-6

y=+2

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