5(x-3)=4(x+2)+6

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Solution for 5(x-3)=4(x+2)+6 equation: 



5(x-3)=4(x+2)+6

We move all terms to the left:

5(x-3)-(4(x+2)+6)=0

We multiply parentheses

5x-(4(x+2)+6)-15=0



We calculate terms in parentheses: -(4(x+2)+6), so:

4(x+2)+6

We multiply parentheses

4x+8+6

We add all the numbers together, and all the variables

4x+14

Back to the equation:

-(4x+14)



We get rid of parentheses

5x-4x-14-15=0

We add all the numbers together, and all the variables

x-29=0

We move all terms containing x to the left, all other terms to the right

x=29

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