2(y+1)+4y=4(y+2)

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Solution for 2(y+1)+4y=4(y+2) equation: 



2(y+1)+4y=4(y+2)

We move all terms to the left:

2(y+1)+4y-(4(y+2))=0

We add all the numbers together, and all the variables

4y+2(y+1)-(4(y+2))=0

We multiply parentheses

4y+2y-(4(y+2))+2=0



We calculate terms in parentheses: -(4(y+2)), so:

4(y+2)

We multiply parentheses

4y+8

Back to the equation:

-(4y+8)



We add all the numbers together, and all the variables

6y-(4y+8)+2=0

We get rid of parentheses

6y-4y-8+2=0

We add all the numbers together, and all the variables

2y-6=0

We move all terms containing y to the left, all other terms to the right

2y=6

y=6/2

y=3

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