(6y+5)(5y+2)=0

Solution for (6y+5)(5y+2)=0 equation:

(6y+5)(5y+2)=0

We multiply parentheses ..

(+30y^2+12y+25y+10)=0

We get rid of parentheses

30y^2+12y+25y+10=0

We add all the numbers together, and all the variables

30y^2+37y+10=0

a = 30; b = 37; c = +10;
Δ = b2-4ac
Δ = 372-4·30·10
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-13}{2*30}=\frac{-50}{60}
=-5/6
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+13}{2*30}=\frac{-24}{60}
=-2/5
$