2(x2+4x-1)=3(x-1)2

Solution for 2(x2+4x-1)=3(x-1)2 equation:

2(x2+4x-1)=3(x-1)2

We move all terms to the left:

2(x2+4x-1)-(3(x-1)2)=0

We add all the numbers together, and all the variables

2(+x^2+4x-1)-(3(x-1)2)=0

We multiply parentheses

2x^2+8x-(3(x-1)2)-2=0


We calculate terms in parentheses: -(3(x-1)2), so:

3(x-1)2

We multiply parentheses

6x-6

Back to the equation:

-(6x-6)


We get rid of parentheses

2x^2+8x-6x+6-2=0

We add all the numbers together, and all the variables

2x^2+2x+4=0

a = 2; b = 2; c = +4;
Δ = b2-4ac
Δ = 22-4·2·4
Δ = -28
Delta is less than zero, so there is no solution for the equation