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(X+3)(X-3)-X(X-5)=6
We move all terms to the left:
(X+3)(X-3)-X(X-5)-(6)=0
We use the square of the difference formula
X^2-X(X-5)-9-6=0
We multiply parentheses
X^2-X^2+5X-9-6=0
We add all the numbers together, and all the variables
5X-15=0
We move all terms containing X to the left, all other terms to the right
5X=15
X=15/5
X=3
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