2(x-7)=4(3x+2)+8

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Solution for 2(x-7)=4(3x+2)+8 equation:



2(x-7)=4(3x+2)+8
We move all terms to the left:
2(x-7)-(4(3x+2)+8)=0
We multiply parentheses
2x-(4(3x+2)+8)-14=0
We calculate terms in parentheses: -(4(3x+2)+8), so:
4(3x+2)+8
We multiply parentheses
12x+8+8
We add all the numbers together, and all the variables
12x+16
Back to the equation:
-(12x+16)
We get rid of parentheses
2x-12x-16-14=0
We add all the numbers together, and all the variables
-10x-30=0
We move all terms containing x to the left, all other terms to the right
-10x=30
x=30/-10
x=-3

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