1/4x-24=16+3/2x

Solution for 1/4x-24=16+3/2x equation:

1/4x-24=16+3/2x

We move all terms to the left:

1/4x-24-(16+3/2x)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

1/4x-(3/2x+16)-24=0

We get rid of parentheses

1/4x-3/2x-16-24=0

We calculate fractions


2x/8x^2+(-12x)/8x^2-16-24=0

We add all the numbers together, and all the variables

2x/8x^2+(-12x)/8x^2-40=0

We multiply all the terms by the denominator


2x+(-12x)-40*8x^2=0

Wy multiply elements

-320x^2+2x+(-12x)=0

We get rid of parentheses

-320x^2+2x-12x=0

We add all the numbers together, and all the variables

-320x^2-10x=0

a = -320; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·(-320)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*-320}=\frac{0}{-640}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*-320}=\frac{20}{-640}
=-1/32
$