2(x-6)+3(x-4)+6(x-2)=8(x-5)+3(x-1)

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Solution for 2(x-6)+3(x-4)+6(x-2)=8(x-5)+3(x-1) equation: 



2(x-6)+3(x-4)+6(x-2)=8(x-5)+3(x-1)

We move all terms to the left:

2(x-6)+3(x-4)+6(x-2)-(8(x-5)+3(x-1))=0

We multiply parentheses

2x+3x+6x-(8(x-5)+3(x-1))-12-12-12=0



We calculate terms in parentheses: -(8(x-5)+3(x-1)), so:

8(x-5)+3(x-1)

We multiply parentheses

8x+3x-40-3

We add all the numbers together, and all the variables

11x-43

Back to the equation:

-(11x-43)



We add all the numbers together, and all the variables

11x-(11x-43)-36=0

We get rid of parentheses

11x-11x+43-36=0

We add all the numbers together, and all the variables

7!=0

There is no solution for this equation

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