-9+12+4(3x-3)=7(x-2)-4x=44

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Solution for -9+12+4(3x-3)=7(x-2)-4x=44 equation: 



-9+12+4(3x-3)=7(x-2)-4x=44

We move all terms to the left:

-9+12+4(3x-3)-(7(x-2)-4x)=0

We add all the numbers together, and all the variables

4(3x-3)-(7(x-2)-4x)+3=0

We multiply parentheses

12x-(7(x-2)-4x)-12+3=0



We calculate terms in parentheses: -(7(x-2)-4x), so:

7(x-2)-4x

We add all the numbers together, and all the variables

-4x+7(x-2)

We multiply parentheses

-4x+7x-14

We add all the numbers together, and all the variables

3x-14

Back to the equation:

-(3x-14)



We add all the numbers together, and all the variables

12x-(3x-14)-9=0

We get rid of parentheses

12x-3x+14-9=0

We add all the numbers together, and all the variables

9x+5=0

We move all terms containing x to the left, all other terms to the right

9x=-5

x=-5/9

x=-5/9

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