3k-2k(6+-9k)=-9k

Solution for 3k-2k(6+-9k)=-9k equation:

3k-2k(6+-9k)=-9k

We move all terms to the left:

3k-2k(6+-9k)-(-9k)=0

We add all the numbers together, and all the variables

3k-2k(-9k)-(-9k)=0

We multiply parentheses

18k^2+3k-(-9k)=0

We get rid of parentheses

18k^2+3k+9k=0

We add all the numbers together, and all the variables

18k^2+12k=0

a = 18; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·18·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*18}=\frac{-24}{36}
=-2/3
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*18}=\frac{0}{36}
=0
$