2(x-5)-5(x-2)=x+9-(x-12)

Solution for 2(x-5)-5(x-2)=x+9-(x-12) equation:

2(x-5)-5(x-2)=x+9-(x-12)

We move all terms to the left:

2(x-5)-5(x-2)-(x+9-(x-12))=0

We multiply parentheses

2x-5x-(x+9-(x-12))-10+10=0


We calculate terms in parentheses: -(x+9-(x-12)), so:

x+9-(x-12)

determiningTheFunctionDomain
x-(x-12)+9

We get rid of parentheses

x-x+12+9

We add all the numbers together, and all the variables

21

Back to the equation:

-(21)


We add all the numbers together, and all the variables

-3x-21=0

We move all terms containing x to the left, all other terms to the right

-3x=21

x=21/-3

x=-7