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7-10=3/(x+1)
We move all terms to the left:
7-10-(3/(x+1))=0
Domain of the equation: (x+1))!=0We add all the numbers together, and all the variables
x∈R
-(3/(x+1))-3=0
We multiply all the terms by the denominator
-(3-3*(x+1))=0
We calculate terms in parentheses: -(3-3*(x+1)), so:We get rid of parentheses
3-3*(x+1)
determiningTheFunctionDomain -3*(x+1)+3
We multiply parentheses
-3x-3+3
We add all the numbers together, and all the variables
-3x
Back to the equation:
-(-3x)
3x=0
x=0/3
x=0
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