2(x-5)+x=7(3-x)+9

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Solution for 2(x-5)+x=7(3-x)+9 equation: 



2(x-5)+x=7(3-x)+9

We move all terms to the left:

2(x-5)+x-(7(3-x)+9)=0

We add all the numbers together, and all the variables

2(x-5)+x-(7(-1x+3)+9)=0

We add all the numbers together, and all the variables

x+2(x-5)-(7(-1x+3)+9)=0

We multiply parentheses

x+2x-(7(-1x+3)+9)-10=0



We calculate terms in parentheses: -(7(-1x+3)+9), so:

7(-1x+3)+9

We multiply parentheses

-7x+21+9

We add all the numbers together, and all the variables

-7x+30

Back to the equation:

-(-7x+30)



We add all the numbers together, and all the variables

3x-(-7x+30)-10=0

We get rid of parentheses

3x+7x-30-10=0

We add all the numbers together, and all the variables

10x-40=0

We move all terms containing x to the left, all other terms to the right

10x=40

x=40/10

x=4

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