2(x-5)+x=7(3-x)+

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Solution for 2(x-5)+x=7(3-x)+ equation: 



2(x-5)+x=7(3-x)+

We move all terms to the left:

2(x-5)+x-(7(3-x)+)=0

We add all the numbers together, and all the variables

2(x-5)+x-(7(-1x+3)+)=0

We add all the numbers together, and all the variables

x+2(x-5)-(7(-1x+3)+)=0

We multiply parentheses

x+2x-(7(-1x+3)+)-10=0



We calculate terms in parentheses: -(7(-1x+3)+), so:

7(-1x+3)+

We add all the numbers together, and all the variables

7(-1x+3)

We multiply parentheses

-7x+21

Back to the equation:

-(-7x+21)



We add all the numbers together, and all the variables

3x-(-7x+21)-10=0

We get rid of parentheses

3x+7x-21-10=0

We add all the numbers together, and all the variables

10x-31=0

We move all terms containing x to the left, all other terms to the right

10x=31

x=31/10

x=3+1/10

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