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2(x-5)+2=6x-4(3+x)
We move all terms to the left:
2(x-5)+2-(6x-4(3+x))=0
We add all the numbers together, and all the variables
2(x-5)-(6x-4(x+3))+2=0
We multiply parentheses
2x-(6x-4(x+3))-10+2=0
We calculate terms in parentheses: -(6x-4(x+3)), so:We add all the numbers together, and all the variables
6x-4(x+3)
We multiply parentheses
6x-4x-12
We add all the numbers together, and all the variables
2x-12
Back to the equation:
-(2x-12)
2x-(2x-12)-8=0
We get rid of parentheses
2x-2x+12-8=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation
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