4.9x2=45

Solution for 4.9x2=45 equation:

4.9x^2=45

We move all terms to the left:

4.9x^2-(45)=0

a = 4.9; b = 0; c = -45;
Δ = b2-4ac
Δ = 02-4·4.9·(-45)
Δ = 882
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{882}=\sqrt{441*2}=\sqrt{441}*\sqrt{2}=21\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-21\sqrt{2}}{2*4.9}=\frac{0-21\sqrt{2}}{9.8}
=-\frac{21\sqrt{2}}{9.8}
=-\frac{7\sqrt{2}}{3.2666666666667}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+21\sqrt{2}}{2*4.9}=\frac{0+21\sqrt{2}}{9.8}
=\frac{21\sqrt{2}}{9.8}
=\frac{7\sqrt{2}}{3.2666666666667}
$