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2(x-4)=4x+-(2x+4)
We move all terms to the left:
2(x-4)-(4x+-(2x+4))=0
We use the square of the difference formula
2(x-4)-(4x-(2x+4))=0
We multiply parentheses
2x-(4x-(2x+4))-8=0
We calculate terms in parentheses: -(4x-(2x+4)), so:We get rid of parentheses
4x-(2x+4)
We get rid of parentheses
4x-2x-4
We add all the numbers together, and all the variables
2x-4
Back to the equation:
-(2x-4)
2x-2x+4-8=0
We add all the numbers together, and all the variables
-4!=0
There is no solution for this equation
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