(8x-11)(6x+17)=0

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Solution for (8x-11)(6x+17)=0 equation:



(8x-11)(6x+17)=0
We multiply parentheses ..
(+48x^2+136x-66x-187)=0
We get rid of parentheses
48x^2+136x-66x-187=0
We add all the numbers together, and all the variables
48x^2+70x-187=0
a = 48; b = 70; c = -187;
Δ = b2-4ac
Δ = 702-4·48·(-187)
Δ = 40804
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{40804}=202$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-202}{2*48}=\frac{-272}{96} =-2+5/6 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+202}{2*48}=\frac{132}{96} =1+3/8 $

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