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1/3(d-8)-7/2(3d-3)=5/12
We move all terms to the left:
1/3(d-8)-7/2(3d-3)-(5/12)=0
Domain of the equation: 3(d-8)!=0
d∈R
Domain of the equation: 2(3d-3)!=0We add all the numbers together, and all the variables
d∈R
1/3(d-8)-7/2(3d-3)-(+5/12)=0
We get rid of parentheses
1/3(d-8)-7/2(3d-3)-5/12=0
We calculate fractions
(24d3/(3(d-8)*2(3d-3)*12)+(-252dd/(3(d-8)*2(3d-3)*12)+(-30d^2d/(3(d-8)*2(3d-3)*12)=0
We calculate terms in parentheses: +(24d3/(3(d-8)*2(3d-3)*12)+(-252dd/(3(d-8)*2(3d-3)*12)+(-30d^2d/(3(d-8)*2(3d-3)*12), so:
24d3/(3(d-8)*2(3d-3)*12)+(-252dd/(3(d-8)*2(3d-3)*12)+(-30d^2d/(3(d-8)*2(3d-3)*12
We can not solve this equation
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