2(x-4)-12=6(x-2)+32

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Solution for 2(x-4)-12=6(x-2)+32 equation:



2(x-4)-12=6(x-2)+32
We move all terms to the left:
2(x-4)-12-(6(x-2)+32)=0
We multiply parentheses
2x-(6(x-2)+32)-8-12=0
We calculate terms in parentheses: -(6(x-2)+32), so:
6(x-2)+32
We multiply parentheses
6x-12+32
We add all the numbers together, and all the variables
6x+20
Back to the equation:
-(6x+20)
We add all the numbers together, and all the variables
2x-(6x+20)-20=0
We get rid of parentheses
2x-6x-20-20=0
We add all the numbers together, and all the variables
-4x-40=0
We move all terms containing x to the left, all other terms to the right
-4x=40
x=40/-4
x=-10

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