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(8x-2)=(2x+3)
We move all terms to the left:
(8x-2)-((2x+3))=0
We get rid of parentheses
8x-((2x+3))-2=0
We calculate terms in parentheses: -((2x+3)), so:We get rid of parentheses
(2x+3)
We get rid of parentheses
2x+3
Back to the equation:
-(2x+3)
8x-2x-3-2=0
We add all the numbers together, and all the variables
6x-5=0
We move all terms containing x to the left, all other terms to the right
6x=5
x=5/6
x=5/6
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