2(x-4)+5=3x+(x-5)

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Solution for 2(x-4)+5=3x+(x-5) equation: 



2(x-4)+5=3x+(x-5)

We move all terms to the left:

2(x-4)+5-(3x+(x-5))=0

We multiply parentheses

2x-(3x+(x-5))-8+5=0



We calculate terms in parentheses: -(3x+(x-5)), so:

3x+(x-5)

We get rid of parentheses

3x+x-5

We add all the numbers together, and all the variables

4x-5

Back to the equation:

-(4x-5)



We add all the numbers together, and all the variables

2x-(4x-5)-3=0

We get rid of parentheses

2x-4x+5-3=0

We add all the numbers together, and all the variables

-2x+2=0

We move all terms containing x to the left, all other terms to the right

-2x=-2

x=-2/-2

x=1

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