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2(x-4)+4x=6x+10-2
We move all terms to the left:
2(x-4)+4x-(6x+10-2)=0
We add all the numbers together, and all the variables
2(x-4)+4x-(6x+8)=0
We add all the numbers together, and all the variables
4x+2(x-4)-(6x+8)=0
We multiply parentheses
4x+2x-(6x+8)-8=0
We get rid of parentheses
4x+2x-6x-8-8=0
We add all the numbers together, and all the variables
-16!=0
There is no solution for this equation
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