If it's not what You are looking for type in the equation solver your own equation and let us solve it.
=4A^2
We move all terms to the left:
-(4A^2)=0
a = -4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-4)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$A=\frac{-b}{2a}=\frac{0}{-8}=0$
| -88=8{x-6} | | |x-11|=|2x+11| | | 4t=6t+10 | | -1-5n=5-8n | | x+32=x+54 | | -3=1x-3 | | -2-10z=-9z | | x/3+19=25 | | 3x(3x+5)=5 | | 6x-6+7=4+5x | | -4+6b=7b | | 10+(0.05m)=22 | | 3(4k-7)=135 | | 4(3x+9)=-50+62 | | -5+-4x=2x+4-9 | | 2(t-3)^2=72 | | 3-8x=-5x | | (6x+5)+(4x+5)=90 | | -9+3x-7x=6x-x | | 5-x12=3-7 | | 4(3d-4)=8 | | 3d+4=2+3d1/2 | | p=–12 | | 6x-6+7=4 | | 8p=9p+5 | | u/4-13=29 | | 8j+-4j=-12 | | 8+7x+7=-20 | | 2(t-3)^2-72=0 | | (3x-15)+(2x+20)=80 | | 7=5t^2+25t | | 7x-7=6x-18 |