2(x-4)+3=3x-2(x-2)*

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Solution for 2(x-4)+3=3x-2(x-2)* equation: 



2(x-4)+3=3x-2(x-2)*

We move all terms to the left:

2(x-4)+3-(3x-2(x-2)*)=0

We multiply parentheses

2x-(3x-2(x-2)*)-8+3=0



We calculate terms in parentheses: -(3x-2(x-2)*), so:

3x-2(x-2)*

We multiply parentheses

3x-2x+4

We add all the numbers together, and all the variables

x+4

Back to the equation:

-(x+4)



We add all the numbers together, and all the variables

2x-(x+4)-5=0

We get rid of parentheses

2x-x-4-5=0

We add all the numbers together, and all the variables

x-9=0

We move all terms containing x to the left, all other terms to the right

x=9

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