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2(x+2)=3(x-5)-x
We move all terms to the left:
2(x+2)-(3(x-5)-x)=0
We multiply parentheses
2x-(3(x-5)-x)+4=0
We calculate terms in parentheses: -(3(x-5)-x), so:We get rid of parentheses
3(x-5)-x
We add all the numbers together, and all the variables
-1x+3(x-5)
We multiply parentheses
-1x+3x-15
We add all the numbers together, and all the variables
2x-15
Back to the equation:
-(2x-15)
2x-2x+15+4=0
We add all the numbers together, and all the variables
19!=0
There is no solution for this equation
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