2(x-4)+3(x-9)+5(x-4)+2(x-20)=200

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Solution for 2(x-4)+3(x-9)+5(x-4)+2(x-20)=200 equation: 



2(x-4)+3(x-9)+5(x-4)+2(x-20)=200

We move all terms to the left:

2(x-4)+3(x-9)+5(x-4)+2(x-20)-(200)=0

We multiply parentheses

2x+3x+5x+2x-8-27-20-40-200=0

We add all the numbers together, and all the variables

12x-295=0

We move all terms containing x to the left, all other terms to the right

12x=295

x=295/12

x=24+7/12

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