4(x+7)+3(x-3)+4(x-4)+5(x+8)=150

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Solution for 4(x+7)+3(x-3)+4(x-4)+5(x+8)=150 equation: 



4(x+7)+3(x-3)+4(x-4)+5(x+8)=150

We move all terms to the left:

4(x+7)+3(x-3)+4(x-4)+5(x+8)-(150)=0

We multiply parentheses

4x+3x+4x+5x+28-9-16+40-150=0

We add all the numbers together, and all the variables

16x-107=0

We move all terms containing x to the left, all other terms to the right

16x=107

x=107/16

x=6+11/16

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