2(x-4)+3(x+2)=3(x+5)

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Solution for 2(x-4)+3(x+2)=3(x+5) equation: 



2(x-4)+3(x+2)=3(x+5)

We move all terms to the left:

2(x-4)+3(x+2)-(3(x+5))=0

We multiply parentheses

2x+3x-(3(x+5))-8+6=0



We calculate terms in parentheses: -(3(x+5)), so:

3(x+5)

We multiply parentheses

3x+15

Back to the equation:

-(3x+15)



We add all the numbers together, and all the variables

5x-(3x+15)-2=0

We get rid of parentheses

5x-3x-15-2=0

We add all the numbers together, and all the variables

2x-17=0

We move all terms containing x to the left, all other terms to the right

2x=17

x=17/2

x=8+1/2

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