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5y(3y-1)=y-7
We move all terms to the left:
5y(3y-1)-(y-7)=0
We multiply parentheses
15y^2-5y-(y-7)=0
We get rid of parentheses
15y^2-5y-y+7=0
We add all the numbers together, and all the variables
15y^2-6y+7=0
a = 15; b = -6; c = +7;
Δ = b2-4ac
Δ = -62-4·15·7
Δ = -384
Delta is less than zero, so there is no solution for the equation
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