2(x-3)=8x+3-3(-4x-2)

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Solution for 2(x-3)=8x+3-3(-4x-2) equation: 



2(x-3)=8x+3-3(-4x-2)

We move all terms to the left:

2(x-3)-(8x+3-3(-4x-2))=0

We multiply parentheses

2x-(8x+3-3(-4x-2))-6=0



We calculate terms in parentheses: -(8x+3-3(-4x-2)), so:

8x+3-3(-4x-2)

determiningTheFunctionDomain
8x-3(-4x-2)+3

We multiply parentheses

8x+12x+6+3

We add all the numbers together, and all the variables

20x+9

Back to the equation:

-(20x+9)



We get rid of parentheses

2x-20x-9-6=0

We add all the numbers together, and all the variables

-18x-15=0

We move all terms containing x to the left, all other terms to the right

-18x=15

x=15/-18

x=-5/6

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