1+2y+3=(y+2)

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Solution for 1+2y+3=(y+2) equation: 



1+2y+3=(y+2)

We move all terms to the left:

1+2y+3-((y+2))=0

We add all the numbers together, and all the variables

2y-((y+2))+4=0



We calculate terms in parentheses: -((y+2)), so:

(y+2)

We get rid of parentheses

y+2

Back to the equation:

-(y+2)



We get rid of parentheses

2y-y-2+4=0

We add all the numbers together, and all the variables

y+2=0

We move all terms containing y to the left, all other terms to the right

y=-2

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