2(x-3)=4(2x+4)+8

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Solution for 2(x-3)=4(2x+4)+8 equation: 



2(x-3)=4(2x+4)+8

We move all terms to the left:

2(x-3)-(4(2x+4)+8)=0

We multiply parentheses

2x-(4(2x+4)+8)-6=0



We calculate terms in parentheses: -(4(2x+4)+8), so:

4(2x+4)+8

We multiply parentheses

8x+16+8

We add all the numbers together, and all the variables

8x+24

Back to the equation:

-(8x+24)



We get rid of parentheses

2x-8x-24-6=0

We add all the numbers together, and all the variables

-6x-30=0

We move all terms containing x to the left, all other terms to the right

-6x=30

x=30/-6

x=-5

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