23(2-x)+12x=68

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Solution for 23(2-x)+12x=68 equation: 



23(2-x)+12x=68

We move all terms to the left:

23(2-x)+12x-(68)=0

We add all the numbers together, and all the variables

23(-1x+2)+12x-68=0

We add all the numbers together, and all the variables

12x+23(-1x+2)-68=0

We multiply parentheses

12x-23x+46-68=0

We add all the numbers together, and all the variables

-11x-22=0

We move all terms containing x to the left, all other terms to the right

-11x=22

x=22/-11

x=-2

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