2(x-3)=3(x-2)+3

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Solution for 2(x-3)=3(x-2)+3 equation: 



2(x-3)=3(x-2)+3

We move all terms to the left:

2(x-3)-(3(x-2)+3)=0

We multiply parentheses

2x-(3(x-2)+3)-6=0



We calculate terms in parentheses: -(3(x-2)+3), so:

3(x-2)+3

We multiply parentheses

3x-6+3

We add all the numbers together, and all the variables

3x-3

Back to the equation:

-(3x-3)



We get rid of parentheses

2x-3x+3-6=0

We add all the numbers together, and all the variables

-1x-3=0

We move all terms containing x to the left, all other terms to the right

-x=3

x=3/-1

x=-3

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