0=a(-1+3)(-5+4)

Solution for 0=a(-1+3)(-5+4) equation:

0=a(-1+3)(-5+4)

We move all terms to the left:

0-(a(-1+3)(-5+4))=0

We add all the numbers together, and all the variables

-(a2(-1))+0=0

We add all the numbers together, and all the variables

-(a2(-1))=0


We calculate terms in parentheses: -(a2(-1)), so:

a2(-1)

We multiply parentheses

-1a^2

Back to the equation:

-(-1a^2)


We get rid of parentheses

1a^2=0

We add all the numbers together, and all the variables

a^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{0}{2}=0$