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2(x-3)-5(1+x)=2(1-x)+x+1
We move all terms to the left:
2(x-3)-5(1+x)-(2(1-x)+x+1)=0
We add all the numbers together, and all the variables
2(x-3)-5(x+1)-(2(-1x+1)+x+1)=0
We multiply parentheses
2x-5x-(2(-1x+1)+x+1)-6-5=0
We calculate terms in parentheses: -(2(-1x+1)+x+1), so:We add all the numbers together, and all the variables
2(-1x+1)+x+1
We add all the numbers together, and all the variables
x+2(-1x+1)+1
We multiply parentheses
x-2x+2+1
We add all the numbers together, and all the variables
-1x+3
Back to the equation:
-(-1x+3)
-3x-(-1x+3)-11=0
We get rid of parentheses
-3x+1x-3-11=0
We add all the numbers together, and all the variables
-2x-14=0
We move all terms containing x to the left, all other terms to the right
-2x=14
x=14/-2
x=-7
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