2(x-3)-4(x-2)=5(-x-5)

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Solution for 2(x-3)-4(x-2)=5(-x-5) equation: 



2(x-3)-4(x-2)=5(-x-5)

We move all terms to the left:

2(x-3)-4(x-2)-(5(-x-5))=0

We add all the numbers together, and all the variables

2(x-3)-4(x-2)-(5(-1x-5))=0

We multiply parentheses

2x-4x-(5(-1x-5))-6+8=0



We calculate terms in parentheses: -(5(-1x-5)), so:

5(-1x-5)

We multiply parentheses

-5x-25

Back to the equation:

-(-5x-25)



We add all the numbers together, and all the variables

-2x-(-5x-25)+2=0

We get rid of parentheses

-2x+5x+25+2=0

We add all the numbers together, and all the variables

3x+27=0

We move all terms containing x to the left, all other terms to the right

3x=-27

x=-27/3

x=-9

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