2(x-3)-4(x+1)=5x-38

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Solution for 2(x-3)-4(x+1)=5x-38 equation: 



2(x-3)-4(x+1)=5x-38

We move all terms to the left:

2(x-3)-4(x+1)-(5x-38)=0

We multiply parentheses

2x-4x-(5x-38)-6-4=0

We get rid of parentheses

2x-4x-5x+38-6-4=0

We add all the numbers together, and all the variables

-7x+28=0

We move all terms containing x to the left, all other terms to the right

-7x=-28

x=-28/-7

x=+4

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