2(x-3)+7x=3(3x-2)

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Solution for 2(x-3)+7x=3(3x-2) equation: 



2(x-3)+7x=3(3x-2)

We move all terms to the left:

2(x-3)+7x-(3(3x-2))=0

We add all the numbers together, and all the variables

7x+2(x-3)-(3(3x-2))=0

We multiply parentheses

7x+2x-(3(3x-2))-6=0



We calculate terms in parentheses: -(3(3x-2)), so:

3(3x-2)

We multiply parentheses

9x-6

Back to the equation:

-(9x-6)



We add all the numbers together, and all the variables

9x-(9x-6)-6=0

We get rid of parentheses

9x-9x+6-6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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