(1/2)(8y-6)=5y-(y+3)

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Solution for (1/2)(8y-6)=5y-(y+3) equation: 



(1/2)(8y-6)=5y-(y+3)

We move all terms to the left:

(1/2)(8y-6)-(5y-(y+3))=0



Domain of the equation: 2)(8y-6)!=0

y∈R



We add all the numbers together, and all the variables

(+1/2)(8y-6)-(5y-(y+3))=0

We multiply parentheses ..

(+8y^2+1/2*-6)-(5y-(y+3))=0

We multiply all the terms by the denominator


(+8y^2+1-((5y-(y+3)))*2*-6)=0



We calculate terms in parentheses: +(+8y^2+1-((5y-(y+3)))*2*-6), so:

+8y^2+1-((5y-(y+3)))*2*-6

determiningTheFunctionDomain
8y^2-((5y-(y+3)))*2*+1-6

We add all the numbers together, and all the variables

8y^2-((5y-(y+3)))*2*-5

Back to the equation:

+(8y^2-((5y-(y+3)))*2*-5)





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((5y-(y+3)))*2*-5), so:

8y^2-((5y-(y+3)))*2*-5





We calculate terms in parentheses: +(8y^2-((

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