2(x-3)+5=10+2(x-1)

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Solution for 2(x-3)+5=10+2(x-1) equation: 



2(x-3)+5=10+2(x-1)

We move all terms to the left:

2(x-3)+5-(10+2(x-1))=0

We multiply parentheses

2x-(10+2(x-1))-6+5=0



We calculate terms in parentheses: -(10+2(x-1)), so:

10+2(x-1)

determiningTheFunctionDomain
2(x-1)+10

We multiply parentheses

2x-2+10

We add all the numbers together, and all the variables

2x+8

Back to the equation:

-(2x+8)



We add all the numbers together, and all the variables

2x-(2x+8)-1=0

We get rid of parentheses

2x-2x-8-1=0

We add all the numbers together, and all the variables

-9!=0

There is no solution for this equation

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