1+y=(4+3y)/2

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Solution for 1+y=(4+3y)/2 equation: 



1+y=(4+3y)/2

We move all terms to the left:

1+y-((4+3y)/2)=0

We add all the numbers together, and all the variables

y-((3y+4)/2)+1=0

We multiply all the terms by the denominator


y*2)-((3y+4)+1*2)=0

We add all the numbers together, and all the variables

y*2)-((3y+4)=0

Wy multiply elements

2y^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{4}=0$

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