2(x-2)=3(x+2)+15

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Solution for 2(x-2)=3(x+2)+15 equation: 



2(x-2)=3(x+2)+15

We move all terms to the left:

2(x-2)-(3(x+2)+15)=0

We multiply parentheses

2x-(3(x+2)+15)-4=0



We calculate terms in parentheses: -(3(x+2)+15), so:

3(x+2)+15

We multiply parentheses

3x+6+15

We add all the numbers together, and all the variables

3x+21

Back to the equation:

-(3x+21)



We get rid of parentheses

2x-3x-21-4=0

We add all the numbers together, and all the variables

-1x-25=0

We move all terms containing x to the left, all other terms to the right

-x=25

x=25/-1

x=-25

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