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2(x-2)=2x+4-2(-9x-3)
We move all terms to the left:
2(x-2)-(2x+4-2(-9x-3))=0
We multiply parentheses
2x-(2x+4-2(-9x-3))-4=0
We calculate terms in parentheses: -(2x+4-2(-9x-3)), so:We get rid of parentheses
2x+4-2(-9x-3)
determiningTheFunctionDomain 2x-2(-9x-3)+4
We multiply parentheses
2x+18x+6+4
We add all the numbers together, and all the variables
20x+10
Back to the equation:
-(20x+10)
2x-20x-10-4=0
We add all the numbers together, and all the variables
-18x-14=0
We move all terms containing x to the left, all other terms to the right
-18x=14
x=14/-18
x=-7/9
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