3(c+4)-c=18

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Solution for 3(c+4)-c=18 equation: 



3(c+4)-c=18

We move all terms to the left:

3(c+4)-c-(18)=0

We add all the numbers together, and all the variables

-1c+3(c+4)-18=0

We multiply parentheses

-1c+3c+12-18=0

We add all the numbers together, and all the variables

2c-6=0

We move all terms containing c to the left, all other terms to the right

2c=6

c=6/2

c=3

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