2(x-2)=1+2(3x+3)

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Solution for 2(x-2)=1+2(3x+3) equation: 



2(x-2)=1+2(3x+3)

We move all terms to the left:

2(x-2)-(1+2(3x+3))=0

We multiply parentheses

2x-(1+2(3x+3))-4=0



We calculate terms in parentheses: -(1+2(3x+3)), so:

1+2(3x+3)

determiningTheFunctionDomain
2(3x+3)+1

We multiply parentheses

6x+6+1

We add all the numbers together, and all the variables

6x+7

Back to the equation:

-(6x+7)



We get rid of parentheses

2x-6x-7-4=0

We add all the numbers together, and all the variables

-4x-11=0

We move all terms containing x to the left, all other terms to the right

-4x=11

x=11/-4

x=-2+3/4

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