4(x+5)=10(x+-3)

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Solution for 4(x+5)=10(x+-3) equation: 



4(x+5)=10(x+-3)

We move all terms to the left:

4(x+5)-(10(x+-3))=0

We add all the numbers together, and all the variables

4(x+5)-(10(x-3))=0

We multiply parentheses

4x-(10(x-3))+20=0



We calculate terms in parentheses: -(10(x-3)), so:

10(x-3)

We multiply parentheses

10x-30

Back to the equation:

-(10x-30)



We get rid of parentheses

4x-10x+30+20=0

We add all the numbers together, and all the variables

-6x+50=0

We move all terms containing x to the left, all other terms to the right

-6x=-50

x=-50/-6

x=8+1/3

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